(5/x-1)+(8/x+1)=(4/x^2-1)

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Solution for (5/x-1)+(8/x+1)=(4/x^2-1) equation: 



(5/x-1)+(8/x+1)=(4/x^2-1)

We move all terms to the left:

(5/x-1)+(8/x+1)-((4/x^2-1))=0



Domain of the equation: x-1)!=0

x∈R





Domain of the equation: x+1)!=0

x∈R





Domain of the equation: x^2-1))!=0

x∈R



We get rid of parentheses

5/x+8/x-((4/x^2-1))-1+1=0

We calculate fractions

We do not support expression: x^3

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